व्यंजक \(3x^2+2\sqrt{x}+5\) (x) में बहुपद क्यों नहीं है?

Why is \(3x^2+2\sqrt{x}+5\) not a polynomial in (x)?

Explanation opens after your attempt
Correct Answer

B. क्योंकि \(\sqrt{x}=x^{\frac{1}{2}}\) हैBecause \(\sqrt{x}=x^{\frac{1}{2}}\)

Step 1

Concept

In \(\sqrt{x}\), the power of the variable is \(\frac{1}{2}\). In a polynomial, the variable power must be a non-negative integer.

Step 2

Why this answer is correct

The correct answer is B. क्योंकि \(\sqrt{x}=x^{\frac{1}{2}}\) है / Because \(\sqrt{x}=x^{\frac{1}{2}}\). In \(\sqrt{x}\), the power of the variable is \(\frac{1}{2}\). In a polynomial, the variable power must be a non-negative integer.

Step 3

Exam Tip

\(\sqrt{x}\) में चर की घात \(\frac{1}{2}\) है। बहुपद में चर की घात अऋणात्मक पूर्णांक होनी चाहिए।

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Mathematics Answer, Explanation and Revision Hints

व्यंजक \(3x^2+2\sqrt{x}+5\) (x) में बहुपद क्यों नहीं है? / Why is \(3x^2+2\sqrt{x}+5\) not a polynomial in (x)?

Correct Answer: B. क्योंकि \(\sqrt{x}=x^{\frac{1}{2}}\) है / Because \(\sqrt{x}=x^{\frac{1}{2}}\). Explanation: \(\sqrt{x}\) में चर की घात \(\frac{1}{2}\) है। बहुपद में चर की घात अऋणात्मक पूर्णांक होनी चाहिए। / In \(\sqrt{x}\), the power of the variable is \(\frac{1}{2}\). In a polynomial, the variable power must be a non-negative integer.

Which concept should I revise for this Mathematics MCQ?

In \(\sqrt{x}\), the power of the variable is \(\frac{1}{2}\). In a polynomial, the variable power must be a non-negative integer.

What exam hint can help solve this Mathematics question?

\(\sqrt{x}\) में चर की घात \(\frac{1}{2}\) है। बहुपद में चर की घात अऋणात्मक पूर्णांक होनी चाहिए।