गुणोत्तर श्रेणी \(2,8,32,\ldots\) का कौन-सा पद (8192) है?

Which term of the geometric progression \(2,8,32,\ldots\) is (8192)?

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Correct Answer

B. सातवाँ पद(7)th term

Step 1

Concept

From \(2\cdot4^{n-1}=8192\), \(4^{n-1}=4096=4^6\), so (n=7). In exams, equate powers to find the term number.

Step 2

Why this answer is correct

The correct answer is B. सातवाँ पद / (7)th term. From \(2\cdot4^{n-1}=8192\), \(4^{n-1}=4096=4^6\), so (n=7). In exams, equate powers to find the term number.

Step 3

Exam Tip

\(2\cdot4^{n-1}=8192\) से \(4^{n-1}=4096=4^6\), इसलिए (n=7) है। परीक्षा में घात बराबर करके पद संख्या निकालें।

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Mathematics Answer, Explanation and Revision Hints

गुणोत्तर श्रेणी \(2,8,32,\ldots\) का कौन-सा पद (8192) है? / Which term of the geometric progression \(2,8,32,\ldots\) is (8192)?

Correct Answer: B. सातवाँ पद / (7)th term. Explanation: \(2\cdot4^{n-1}=8192\) से \(4^{n-1}=4096=4^6\), इसलिए (n=7) है। परीक्षा में घात बराबर करके पद संख्या निकालें। / From \(2\cdot4^{n-1}=8192\), \(4^{n-1}=4096=4^6\), so (n=7). In exams, equate powers to find the term number.

Which concept should I revise for this Mathematics MCQ?

From \(2\cdot4^{n-1}=8192\), \(4^{n-1}=4096=4^6\), so (n=7). In exams, equate powers to find the term number.

What exam hint can help solve this Mathematics question?

\(2\cdot4^{n-1}=8192\) से \(4^{n-1}=4096=4^6\), इसलिए (n=7) है। परीक्षा में घात बराबर करके पद संख्या निकालें।