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Which statement is sufficient to reject the rational assumption in the proof of (√3)?

Answer and explanation

Correct answer: Both p and q in lowest form turn out to be divisible by 3

The governing concept is proof by contradiction together with the lowest-form condition for a rational number. Assume √3 = p/q, where p and q are integers, q ≠ 0, and gcd(p,q) = 1. Squaring gives p² = 3q². From this equation, 3 divides p, so p = 3k; substitution then shows that 3 also divides q. Thus p and q have a common factor 3, contradicting gcd(p,q) = 1. Therefore the rational assumption must be rejected. Option A is incomplete because divisibility of p alone does not contradict lowest form; options C and D do not produce the required contradiction.

Related tags

Number-SystemsIrrationalitySquare-Root-3Proof-By-ContradictionProof Of Irrationality Of Square Root 2 And Square Root 3Number SystemsMathematicsClass 9 Mcq

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