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Which statement is an essential basis of the proof by contradiction that \(\sqrt{2}\) is irrational?

Answer and explanation

Correct answer: यदि किसी पूर्णांक का वर्ग सम है, तो वह पूर्णांक भी सम होता है।

Assume \(\sqrt{2}=p/q\) in lowest terms. Then \(p^2=2q^2\), so \(p^2\) is even and hence \(p\) is even. This later makes \(q\) even too, contradicting coprimality. Exam tip: remember that an even square has an even integer root.

Related tags

Number SystemsIrrational NumbersProof By ContradictionSquare Root Of 2ParityProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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