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Which statement correctly identifies why \(\sqrt{2}\) is irrational?

Answer and explanation

Correct answer: Its decimal expansion is non-terminating and non-recurring.

A rational number has a terminating or recurring decimal expansion. \(\sqrt{2}\) is non-terminating and non-recurring, so it is irrational; option D describes a rational decimal. Exam tip: look for “non-recurring”.

Related tags

Number SystemsIrrational NumbersSquare Root 2Decimal ExpansionProof Of IrrationalityProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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