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Which statement correctly describes the contradiction obtained while proving that \(\sqrt{2}\) is irrational?

Answer and explanation

Correct answer: Both p and q are divisible by 2, although they were assumed to be coprime

Assume \(\sqrt{2}=p/q\) in lowest terms. From \(p^2=2q^2\), p is even; writing \(p=2k\) then shows q is even too. This contradicts coprimality. Exam tip: begin with lowest terms.

Related tags

Number SystemsIrrational NumbersSquare Root 2Proof By ContradictionCoprime IntegersProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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