कौन सा क्रम \(a_n=3^n-1\) से बने पहले चार पद दिखाता है?

Which sequence shows the first four terms of \(a_n=3^n-1\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. (2,8,26,80)

Step 1

Concept

\(3^1-1=2\), \(3^2-1=8\), \(3^3-1=26\), and \(3^4-1=80\). Evaluate the power and subtract (1).

Step 2

Why this answer is correct

The correct answer is A. (2,8,26,80). \(3^1-1=2\), \(3^2-1=8\), \(3^3-1=26\), and \(3^4-1=80\). Evaluate the power and subtract (1).

Step 3

Exam Tip

\(3^1-1=2\), \(3^2-1=8\), \(3^3-1=26\), \(3^4-1=80\)। घात निकालकर (1) घटाएँ।

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Mathematics Answer, Explanation and Revision Hints

कौन सा क्रम \(a_n=3^n-1\) से बने पहले चार पद दिखाता है? / Which sequence shows the first four terms of \(a_n=3^n-1\)?

Correct Answer: A. (2,8,26,80). Explanation: \(3^1-1=2\), \(3^2-1=8\), \(3^3-1=26\), \(3^4-1=80\)। घात निकालकर (1) घटाएँ। / \(3^1-1=2\), \(3^2-1=8\), \(3^3-1=26\), and \(3^4-1=80\). Evaluate the power and subtract (1).

Which concept should I revise for this Mathematics MCQ?

\(3^1-1=2\), \(3^2-1=8\), \(3^3-1=26\), and \(3^4-1=80\). Evaluate the power and subtract (1).

What exam hint can help solve this Mathematics question?

\(3^1-1=2\), \(3^2-1=8\), \(3^3-1=26\), \(3^4-1=80\)। घात निकालकर (1) घटाएँ।