किस विकल्प में \(\sqrt{3}\) के प्रमाण की गलत बीजगणितीय छलांग है?
Which option shows a wrong algebraic leap in the proof of \(\sqrt{3}\)?
Explanation opens after your attempt
Correct Answer
D. \(u^2=3v^2\Rightarrow u=3v\)
Concept
\(u^2=3v^2\) does not directly give (u=3v). First (u) is proved divisible by (3).
Why this answer is correct
The correct answer is D. \(u^2=3v^2\Rightarrow u=3v\). \(u^2=3v^2\) does not directly give (u=3v). First (u) is proved divisible by (3).
Exam Tip
\(u^2=3v^2\) से सीधे (u=3v) नहीं निकलता। पहले (u) का (3) से विभाज्य होना सिद्ध किया जाता है।
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