किस विकल्प में \(\sqrt{2}\) के प्रमाण की गलत बीजगणितीय छलांग दिखाई गई है?
Which option shows a wrong algebraic leap in the proof of \(\sqrt{2}\)?
Explanation opens after your attempt
D. \(x^2=2y^2\Rightarrow x=2y\)
Concept
The square relation does not directly give (x=2y). The correct path is from \(x^2\) even to (x) even.
Why this answer is correct
The correct answer is D. \(x^2=2y^2\Rightarrow x=2y\). The square relation does not directly give (x=2y). The correct path is from \(x^2\) even to (x) even.
Exam Tip
वर्ग संबंध से सीधे (x=2y) नहीं मिलता। सही रास्ता \(x^2\) सम से (x) सम तक है।
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