कौन-सा विकल्प \(\frac{6}{\sqrt{19}}\) का सही परिमेयकृत रूप है?

Which option is the correct rationalised form of \(\frac{6}{\sqrt{19}}\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. \(\frac{6\sqrt{19}}{19}\)

Step 1

Concept

Multiplying numerator and denominator by \(\sqrt{19}\) gives \(\frac{6\sqrt{19}}{19}\). Rationalisation removes the radical from the denominator.

Step 2

Why this answer is correct

The correct answer is C. \(\frac{6\sqrt{19}}{19}\). Multiplying numerator and denominator by \(\sqrt{19}\) gives \(\frac{6\sqrt{19}}{19}\). Rationalisation removes the radical from the denominator.

Step 3

Exam Tip

अंश और हर को \(\sqrt{19}\) से गुणा करने पर \(\frac{6\sqrt{19}}{19}\) मिलता है। परिमेयकरण में हर से मूल हटता है।

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Mathematics Answer, Explanation and Revision Hints

कौन-सा विकल्प \(\frac{6}{\sqrt{19}}\) का सही परिमेयकृत रूप है? / Which option is the correct rationalised form of \(\frac{6}{\sqrt{19}}\)?

Correct Answer: C. \(\frac{6\sqrt{19}}{19}\). Explanation: अंश और हर को \(\sqrt{19}\) से गुणा करने पर \(\frac{6\sqrt{19}}{19}\) मिलता है। परिमेयकरण में हर से मूल हटता है। / Multiplying numerator and denominator by \(\sqrt{19}\) gives \(\frac{6\sqrt{19}}{19}\). Rationalisation removes the radical from the denominator.

Which concept should I revise for this Mathematics MCQ?

Multiplying numerator and denominator by \(\sqrt{19}\) gives \(\frac{6\sqrt{19}}{19}\). Rationalisation removes the radical from the denominator.

What exam hint can help solve this Mathematics question?

अंश और हर को \(\sqrt{19}\) से गुणा करने पर \(\frac{6\sqrt{19}}{19}\) मिलता है। परिमेयकरण में हर से मूल हटता है।