कौन-सा विकल्प \(\sqrt{72}+\sqrt{128}\) के बराबर है?

Which option is equal to \(\sqrt{72}+\sqrt{128}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(14\sqrt{2}\)

Step 1

Concept

\(\sqrt{72}=6\sqrt{2}\) and \(\sqrt{128}=8\sqrt{2}\). So the sum is \(14\sqrt{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(14\sqrt{2}\). \(\sqrt{72}=6\sqrt{2}\) and \(\sqrt{128}=8\sqrt{2}\). So the sum is \(14\sqrt{2}\).

Step 3

Exam Tip

\(\sqrt{72}=6\sqrt{2}\) और \(\sqrt{128}=8\sqrt{2}\) है। इसलिए योग \(14\sqrt{2}\) है।

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Mathematics Answer, Explanation and Revision Hints

कौन-सा विकल्प \(\sqrt{72}+\sqrt{128}\) के बराबर है? / Which option is equal to \(\sqrt{72}+\sqrt{128}\)?

Correct Answer: A. \(14\sqrt{2}\). Explanation: \(\sqrt{72}=6\sqrt{2}\) और \(\sqrt{128}=8\sqrt{2}\) है। इसलिए योग \(14\sqrt{2}\) है। / \(\sqrt{72}=6\sqrt{2}\) and \(\sqrt{128}=8\sqrt{2}\). So the sum is \(14\sqrt{2}\).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{72}=6\sqrt{2}\) and \(\sqrt{128}=8\sqrt{2}\). So the sum is \(14\sqrt{2}\).

What exam hint can help solve this Mathematics question?

\(\sqrt{72}=6\sqrt{2}\) और \(\sqrt{128}=8\sqrt{2}\) है। इसलिए योग \(14\sqrt{2}\) है।