किस विकल्प में \(\sqrt{3}\) के प्रमाण में गलत प्रारंभिक रूप है?
Which option gives a wrong initial form in the proof of \(\sqrt{3}\)?
Explanation opens after your attempt
Correct Answer
B. \(\sqrt{3}=\frac{p}{0}\)
Concept
\(\frac{p}{0}\) is undefined. The denominator of a rational fraction cannot be zero.
Why this answer is correct
The correct answer is B. \(\sqrt{3}=\frac{p}{0}\). \(\frac{p}{0}\) is undefined. The denominator of a rational fraction cannot be zero.
Exam Tip
\(\frac{p}{0}\) परिभाषित नहीं है। परिमेय भिन्न में हर शून्य नहीं हो सकता।
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