\(\sqrt{98}-\sqrt{50}\) का सरल रूप कौन-सा है?

Which is the simplified form of \(\sqrt{98}-\sqrt{50}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. \(2\sqrt{2}\)

Step 1

Concept

\(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so the difference is \(2\sqrt{2}\). First take out perfect-square factors.

Step 2

Why this answer is correct

The correct answer is C. \(2\sqrt{2}\). \(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so the difference is \(2\sqrt{2}\). First take out perfect-square factors.

Step 3

Exam Tip

\(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\), इसलिए अंतर \(2\sqrt{2}\) है। पहले पूर्ण वर्ग गुणनखंड निकालें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(\sqrt{98}-\sqrt{50}\) का सरल रूप कौन-सा है? / Which is the simplified form of \(\sqrt{98}-\sqrt{50}\)?

Correct Answer: C. \(2\sqrt{2}\). Explanation: \(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\), इसलिए अंतर \(2\sqrt{2}\) है। पहले पूर्ण वर्ग गुणनखंड निकालें। / \(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so the difference is \(2\sqrt{2}\). First take out perfect-square factors.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so the difference is \(2\sqrt{2}\). First take out perfect-square factors.

What exam hint can help solve this Mathematics question?

\(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\), इसलिए अंतर \(2\sqrt{2}\) है। पहले पूर्ण वर्ग गुणनखंड निकालें।