\(\sqrt{32}+\sqrt{18}\) का सरल रूप कौन-सा है?

Which is the simplified form of \(\sqrt{32}+\sqrt{18}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(7\sqrt{2}\)

Step 1

Concept

\(\sqrt{32}=4\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\), so the sum is \(7\sqrt{2}\). First convert radicals into like form.

Step 2

Why this answer is correct

The correct answer is B. \(7\sqrt{2}\). \(\sqrt{32}=4\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\), so the sum is \(7\sqrt{2}\). First convert radicals into like form.

Step 3

Exam Tip

\(\sqrt{32}=4\sqrt{2}\) और \(\sqrt{18}=3\sqrt{2}\), इसलिए योग \(7\sqrt{2}\) है। पहले मूलों को समान रूप में बदलें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(\sqrt{32}+\sqrt{18}\) का सरल रूप कौन-सा है? / Which is the simplified form of \(\sqrt{32}+\sqrt{18}\)?

Correct Answer: B. \(7\sqrt{2}\). Explanation: \(\sqrt{32}=4\sqrt{2}\) और \(\sqrt{18}=3\sqrt{2}\), इसलिए योग \(7\sqrt{2}\) है। पहले मूलों को समान रूप में बदलें। / \(\sqrt{32}=4\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\), so the sum is \(7\sqrt{2}\). First convert radicals into like form.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{32}=4\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\), so the sum is \(7\sqrt{2}\). First convert radicals into like form.

What exam hint can help solve this Mathematics question?

\(\sqrt{32}=4\sqrt{2}\) और \(\sqrt{18}=3\sqrt{2}\), इसलिए योग \(7\sqrt{2}\) है। पहले मूलों को समान रूप में बदलें।