\(\sqrt{162}+\sqrt{72}\) का सरल रूप कौन-सा है?
Which is the simplified form of \(\sqrt{162}+\sqrt{72}\)?
Explanation opens after your attempt
B. \(15\sqrt{2}\)
Concept
\(\sqrt{162}=9\sqrt{2}\) and \(\sqrt{72}=6\sqrt{2}\), so the sum is \(15\sqrt{2}\). Add coefficients of like radicals.
Why this answer is correct
The correct answer is B. \(15\sqrt{2}\). \(\sqrt{162}=9\sqrt{2}\) and \(\sqrt{72}=6\sqrt{2}\), so the sum is \(15\sqrt{2}\). Add coefficients of like radicals.
Exam Tip
\(\sqrt{162}=9\sqrt{2}\) और \(\sqrt{72}=6\sqrt{2}\), इसलिए योग \(15\sqrt{2}\) है। समान मूलों के गुणांक जोड़ें।
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