कौन-सा व्यंजक (x) में बहुपद नहीं है लेकिन (x) के बिना स्थिर पद भी रखता है?

Which expression is not a polynomial in (x) but also has a constant term?

Explanation opens after your attempt
Correct Answer

C. \(x^{-2}+7\)

Step 1

Concept

The power in \(x^{-2}\) is negative, so it is not a polynomial. (7) is only a constant term, and the issue is the negative power.

Step 2

Why this answer is correct

The correct answer is C. \(x^{-2}+7\). The power in \(x^{-2}\) is negative, so it is not a polynomial. (7) is only a constant term, and the issue is the negative power.

Step 3

Exam Tip

\(x^{-2}\) की घात ऋणात्मक है इसलिए यह बहुपद नहीं है। (7) केवल स्थिर पद है और समस्या ऋणात्मक घात से है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

कौन-सा व्यंजक (x) में बहुपद नहीं है लेकिन (x) के बिना स्थिर पद भी रखता है? / Which expression is not a polynomial in (x) but also has a constant term?

Correct Answer: C. \(x^{-2}+7\). Explanation: \(x^{-2}\) की घात ऋणात्मक है इसलिए यह बहुपद नहीं है। (7) केवल स्थिर पद है और समस्या ऋणात्मक घात से है। / The power in \(x^{-2}\) is negative, so it is not a polynomial. (7) is only a constant term, and the issue is the negative power.

Which concept should I revise for this Mathematics MCQ?

The power in \(x^{-2}\) is negative, so it is not a polynomial. (7) is only a constant term, and the issue is the negative power.

What exam hint can help solve this Mathematics question?

\(x^{-2}\) की घात ऋणात्मक है इसलिए यह बहुपद नहीं है। (7) केवल स्थिर पद है और समस्या ऋणात्मक घात से है।