कौन-सा व्यंजक (x) में बहुपद नहीं है क्योंकि उसमें (x) भाजक में छिपा है?

Which expression is not a polynomial in (x) because (x) is hidden in the divisor?

Explanation opens after your attempt
Correct Answer

B. \(\frac{2x^2+5}{x}\)

Step 1

Concept

\(\frac{2x^2+5}{x}=2x+\frac{5}{x}\). In \(\frac{5}{x}\), the power of (x) is (-1).

Step 2

Why this answer is correct

The correct answer is B. \(\frac{2x^2+5}{x}\). \(\frac{2x^2+5}{x}=2x+\frac{5}{x}\). In \(\frac{5}{x}\), the power of (x) is (-1).

Step 3

Exam Tip

\(\frac{2x^2+5}{x}=2x+\frac{5}{x}\) है। \(\frac{5}{x}\) में (x) की घात (-1) है।

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Mathematics Answer, Explanation and Revision Hints

कौन-सा व्यंजक (x) में बहुपद नहीं है क्योंकि उसमें (x) भाजक में छिपा है? / Which expression is not a polynomial in (x) because (x) is hidden in the divisor?

Correct Answer: B. \(\frac{2x^2+5}{x}\). Explanation: \(\frac{2x^2+5}{x}=2x+\frac{5}{x}\) है। \(\frac{5}{x}\) में (x) की घात (-1) है। / \(\frac{2x^2+5}{x}=2x+\frac{5}{x}\). In \(\frac{5}{x}\), the power of (x) is (-1).

Which concept should I revise for this Mathematics MCQ?

\(\frac{2x^2+5}{x}=2x+\frac{5}{x}\). In \(\frac{5}{x}\), the power of (x) is (-1).

What exam hint can help solve this Mathematics question?

\(\frac{2x^2+5}{x}=2x+\frac{5}{x}\) है। \(\frac{5}{x}\) में (x) की घात (-1) है।