कौन-सा व्यंजक बहुपद नहीं है क्योंकि चर मूल के अंदर है?

Which expression is not a polynomial because the variable is inside a root?

Explanation opens after your attempt
Correct Answer

B. \(\sqrt{x}+3\)

Step 1

Concept

\(\sqrt{x}=x^{1/2}\), and \(\frac{1}{2}\) is not an integer power. Hence it is not a polynomial.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{x}+3\). \(\sqrt{x}=x^{1/2}\), and \(\frac{1}{2}\) is not an integer power. Hence it is not a polynomial.

Step 3

Exam Tip

\(\sqrt{x}=x^{1/2}\) होता है और \(\frac{1}{2}\) पूर्णांक घात नहीं है। इसलिए यह बहुपद नहीं है।

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Mathematics Answer, Explanation and Revision Hints

कौन-सा व्यंजक बहुपद नहीं है क्योंकि चर मूल के अंदर है? / Which expression is not a polynomial because the variable is inside a root?

Correct Answer: B. \(\sqrt{x}+3\). Explanation: \(\sqrt{x}=x^{1/2}\) होता है और \(\frac{1}{2}\) पूर्णांक घात नहीं है। इसलिए यह बहुपद नहीं है। / \(\sqrt{x}=x^{1/2}\), and \(\frac{1}{2}\) is not an integer power. Hence it is not a polynomial.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{x}=x^{1/2}\), and \(\frac{1}{2}\) is not an integer power. Hence it is not a polynomial.

What exam hint can help solve this Mathematics question?

\(\sqrt{x}=x^{1/2}\) होता है और \(\frac{1}{2}\) पूर्णांक घात नहीं है। इसलिए यह बहुपद नहीं है।