किस व्यंजक में चर हर में छिपा होने के कारण वह बहुपद नहीं है?

Which expression is not a polynomial because the variable is hidden in the denominator?

Explanation opens after your attempt
Correct Answer

B. \(\frac{x^2+4}{x}\)

Step 1

Concept

\(\frac{x^2+4}{x}=x+\frac{4}{x}\) contains \(\frac{4}{x}\), whose power is (-1). Hence it is not a polynomial.

Step 2

Why this answer is correct

The correct answer is B. \(\frac{x^2+4}{x}\). \(\frac{x^2+4}{x}=x+\frac{4}{x}\) contains \(\frac{4}{x}\), whose power is (-1). Hence it is not a polynomial.

Step 3

Exam Tip

\(\frac{x^2+4}{x}=x+\frac{4}{x}\) में \(\frac{4}{x}\) की घात (-1) है। इसलिए यह बहुपद नहीं है।

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किस व्यंजक में चर हर में छिपा होने के कारण वह बहुपद नहीं है? / Which expression is not a polynomial because the variable is hidden in the denominator?

Correct Answer: B. \(\frac{x^2+4}{x}\). Explanation: \(\frac{x^2+4}{x}=x+\frac{4}{x}\) में \(\frac{4}{x}\) की घात (-1) है। इसलिए यह बहुपद नहीं है। / \(\frac{x^2+4}{x}=x+\frac{4}{x}\) contains \(\frac{4}{x}\), whose power is (-1). Hence it is not a polynomial.

Which concept should I revise for this Mathematics MCQ?

\(\frac{x^2+4}{x}=x+\frac{4}{x}\) contains \(\frac{4}{x}\), whose power is (-1). Hence it is not a polynomial.

What exam hint can help solve this Mathematics question?

\(\frac{x^2+4}{x}=x+\frac{4}{x}\) में \(\frac{4}{x}\) की घात (-1) है। इसलिए यह बहुपद नहीं है।