कौन-सा व्यंजक (x) में बहुपद है यदि (a) को स्थिर माना जाए?

Which expression is a polynomial in (x) if (a) is treated as a constant?

Explanation opens after your attempt
Correct Answer

A. \(ax^2+3x-1\)

Step 1

Concept

Treating (a) as a constant, \(ax^2\) has (x)-power (2). All powers of (x) are non-negative integers.

Step 2

Why this answer is correct

The correct answer is A. \(ax^2+3x-1\). Treating (a) as a constant, \(ax^2\) has (x)-power (2). All powers of (x) are non-negative integers.

Step 3

Exam Tip

(a) को स्थिर मानने पर \(ax^2\) में (x) की घात (2) है। सभी (x) घातें शून्य या धनात्मक पूर्णांक हैं।

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Mathematics Answer, Explanation and Revision Hints

कौन-सा व्यंजक (x) में बहुपद है यदि (a) को स्थिर माना जाए? / Which expression is a polynomial in (x) if (a) is treated as a constant?

Correct Answer: A. \(ax^2+3x-1\). Explanation: (a) को स्थिर मानने पर \(ax^2\) में (x) की घात (2) है। सभी (x) घातें शून्य या धनात्मक पूर्णांक हैं। / Treating (a) as a constant, \(ax^2\) has (x)-power (2). All powers of (x) are non-negative integers.

Which concept should I revise for this Mathematics MCQ?

Treating (a) as a constant, \(ax^2\) has (x)-power (2). All powers of (x) are non-negative integers.

What exam hint can help solve this Mathematics question?

(a) को स्थिर मानने पर \(ax^2\) में (x) की घात (2) है। सभी (x) घातें शून्य या धनात्मक पूर्णांक हैं।