कौन-सा व्यंजक (x) में बहुपद है, पर (x) में स्थिर बहुपद नहीं है?

Which expression is a polynomial in (x), but not a constant polynomial in (x)?

Explanation opens after your attempt
Correct Answer

C. \(3x^2+1\)

Step 1

Concept

\(3x^2+1\) contains the variable (x) and has degree (2). Therefore, it is not a constant polynomial.

Step 2

Why this answer is correct

The correct answer is C. \(3x^2+1\). \(3x^2+1\) contains the variable (x) and has degree (2). Therefore, it is not a constant polynomial.

Step 3

Exam Tip

\(3x^2+1\) में चर (x) मौजूद है और घात (2) है। इसलिए यह स्थिर बहुपद नहीं है।

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Mathematics Answer, Explanation and Revision Hints

कौन-सा व्यंजक (x) में बहुपद है, पर (x) में स्थिर बहुपद नहीं है? / Which expression is a polynomial in (x), but not a constant polynomial in (x)?

Correct Answer: C. \(3x^2+1\). Explanation: \(3x^2+1\) में चर (x) मौजूद है और घात (2) है। इसलिए यह स्थिर बहुपद नहीं है। / \(3x^2+1\) contains the variable (x) and has degree (2). Therefore, it is not a constant polynomial.

Which concept should I revise for this Mathematics MCQ?

\(3x^2+1\) contains the variable (x) and has degree (2). Therefore, it is not a constant polynomial.

What exam hint can help solve this Mathematics question?

\(3x^2+1\) में चर (x) मौजूद है और घात (2) है। इसलिए यह स्थिर बहुपद नहीं है।