कौन-सी श्रृंखला \(\sqrt{3}\) के प्रमाण की सबसे सटीक संरचना देती है?

Which chain gives the most accurate structure of the proof of \(\sqrt{3}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. परिमेय मान्यता \(\rightarrow\) \(u^2=3v^2\) \(\rightarrow\) (u) (3) से विभाज्य \(\rightarrow\) (v) (3) से विभाज्य \(\rightarrow\) सहभाज्य विरोधाभासRational assumption \(\rightarrow\) \(u^2=3v^2\) \(\rightarrow\) (u) divisible by (3) \(\rightarrow\) (v) divisible by (3)

Step 1

Concept

For \(\sqrt{3}\), a chain of divisibility by (3) is formed. Finally common factor (3) gives contradiction.

Step 2

Why this answer is correct

The correct answer is A. परिमेय मान्यता \(\rightarrow\) \(u^2=3v^2\) \(\rightarrow\) (u) (3) से विभाज्य \(\rightarrow\) (v) (3) से विभाज्य \(\rightarrow\) सहभाज्य विरोधाभास / Rational assumption \(\rightarrow\) \(u^2=3v^2\) \(\rightarrow\) (u) divisible by (3) \(\rightarrow\) (v) divisible by (3). For \(\sqrt{3}\), a chain of divisibility by (3) is formed. Finally common factor (3) gives contradiction.

Step 3

Exam Tip

\(\sqrt{3}\) में (3) से विभाज्यता की श्रृंखला बनती है। अंत में दोनों में सामान्य गुणनखंड (3) विरोधाभास देता है।

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Mathematics Answer, Explanation and Revision Hints

कौन-सी श्रृंखला \(\sqrt{3}\) के प्रमाण की सबसे सटीक संरचना देती है? / Which chain gives the most accurate structure of the proof of \(\sqrt{3}\)?

Correct Answer: A. परिमेय मान्यता \(\rightarrow\) \(u^2=3v^2\) \(\rightarrow\) (u) (3) से विभाज्य \(\rightarrow\) (v) (3) से विभाज्य \(\rightarrow\) सहभाज्य विरोधाभास / Rational assumption \(\rightarrow\) \(u^2=3v^2\) \(\rightarrow\) (u) divisible by (3) \(\rightarrow\) (v) divisible by (3). Explanation: \(\sqrt{3}\) में (3) से विभाज्यता की श्रृंखला बनती है। अंत में दोनों में सामान्य गुणनखंड (3) विरोधाभास देता है। / For \(\sqrt{3}\), a chain of divisibility by (3) is formed. Finally common factor (3) gives contradiction.

Which concept should I revise for this Mathematics MCQ?

For \(\sqrt{3}\), a chain of divisibility by (3) is formed. Finally common factor (3) gives contradiction.

What exam hint can help solve this Mathematics question?

\(\sqrt{3}\) में (3) से विभाज्यता की श्रृंखला बनती है। अंत में दोनों में सामान्य गुणनखंड (3) विरोधाभास देता है।