किस समांतर श्रेणी का (n)वाँ पद \(a_n=6n+1\) है?
Which arithmetic progression has (n)th term \(a_n=6n+1\)?
Explanation opens after your attempt
C. \(7,13,19,25,\ldots\)
Concept
Putting (n=1,2,3,4) gives \(7,13,19,25,\ldots\). Form the initial terms from the rule and match the option.
Why this answer is correct
The correct answer is C. \(7,13,19,25,\ldots\). Putting (n=1,2,3,4) gives \(7,13,19,25,\ldots\). Form the initial terms from the rule and match the option.
Exam Tip
(n=1,2,3,4) रखने पर \(7,13,19,25,\ldots\) मिलता है। नियम से शुरू के पद बनाकर विकल्प मिलाएं।
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