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When irrationality of \(\sqrt{3}\) is proved, which conclusion is correct?

Answer and explanation

Correct answer: \(\sqrt{3}\) is not rational

An irrational number cannot be written in the form \(p/q\), where \(p\) and \(q\) are integers and \(q\ne0\). Hence, proving that \(\sqrt{3}\) is irrational directly means that \(\sqrt{3}\) is not rational. It is neither an integer nor zero nor negative; in fact, \(\sqrt{3}>0\). Exam tip: remember that “irrational” means “not rational.”

Related tags

Number SystemsIrrational NumbersSquare Root 3Proof Of IrrationalityClass 9 MathematicsProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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