अनुक्रम \(\frac{3}{4},\frac{5}{7},\frac{7}{10},\ldots\) में (9)वाँ पद क्या होगा?

What will be the (9)th term in the sequence \(\frac{3}{4},\frac{5}{7},\frac{7}{10},\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(\frac{19}{28}\)

Step 1

Concept

The general term is \(\frac{2n+1}{3n+1}\), so the (9)th term is \(\frac{19}{28}\). Exam tip: observe numerator and denominator patterns separately.

Step 2

Why this answer is correct

The correct answer is B. \(\frac{19}{28}\). The general term is \(\frac{2n+1}{3n+1}\), so the (9)th term is \(\frac{19}{28}\). Exam tip: observe numerator and denominator patterns separately.

Step 3

Exam Tip

सामान्य पद \(\frac{2n+1}{3n+1}\) है इसलिए (9)वाँ पद \(\frac{19}{28}\) है। अंश और हर का पैटर्न अलग देखें।

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Mathematics Answer, Explanation and Revision Hints

अनुक्रम \(\frac{3}{4},\frac{5}{7},\frac{7}{10},\ldots\) में (9)वाँ पद क्या होगा? / What will be the (9)th term in the sequence \(\frac{3}{4},\frac{5}{7},\frac{7}{10},\ldots\)?

Correct Answer: B. \(\frac{19}{28}\). Explanation: सामान्य पद \(\frac{2n+1}{3n+1}\) है इसलिए (9)वाँ पद \(\frac{19}{28}\) है। अंश और हर का पैटर्न अलग देखें। / The general term is \(\frac{2n+1}{3n+1}\), so the (9)th term is \(\frac{19}{28}\). Exam tip: observe numerator and denominator patterns separately.

Which concept should I revise for this Mathematics MCQ?

The general term is \(\frac{2n+1}{3n+1}\), so the (9)th term is \(\frac{19}{28}\). Exam tip: observe numerator and denominator patterns separately.

What exam hint can help solve this Mathematics question?

सामान्य पद \(\frac{2n+1}{3n+1}\) है इसलिए (9)वाँ पद \(\frac{19}{28}\) है। अंश और हर का पैटर्न अलग देखें।