\( \sqrt{12}+\sqrt{75}-\sqrt{48}-\sqrt{27} \) का मान क्या है?

What is the value of \( \sqrt{12}+\sqrt{75}-\sqrt{48}-\sqrt{27} \)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

They become \(2\sqrt{3},5\sqrt{3},4\sqrt{3},3\sqrt{3}\). Since (2+5-4-3=0), the value is (0).

Step 2

Why this answer is correct

The correct answer is A. (0). They become \(2\sqrt{3},5\sqrt{3},4\sqrt{3},3\sqrt{3}\). Since (2+5-4-3=0), the value is (0).

Step 3

Exam Tip

क्रमशः \(2\sqrt{3},5\sqrt{3},4\sqrt{3},3\sqrt{3}\) मिलते हैं। (2+5-4-3=0) इसलिए मान (0) है।

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Mathematics Answer, Explanation and Revision Hints

\( \sqrt{12}+\sqrt{75}-\sqrt{48}-\sqrt{27} \) का मान क्या है? / What is the value of \( \sqrt{12}+\sqrt{75}-\sqrt{48}-\sqrt{27} \)?

Correct Answer: A. (0). Explanation: क्रमशः \(2\sqrt{3},5\sqrt{3},4\sqrt{3},3\sqrt{3}\) मिलते हैं। (2+5-4-3=0) इसलिए मान (0) है। / They become \(2\sqrt{3},5\sqrt{3},4\sqrt{3},3\sqrt{3}\). Since (2+5-4-3=0), the value is (0).

Which concept should I revise for this Mathematics MCQ?

They become \(2\sqrt{3},5\sqrt{3},4\sqrt{3},3\sqrt{3}\). Since (2+5-4-3=0), the value is (0).

What exam hint can help solve this Mathematics question?

क्रमशः \(2\sqrt{3},5\sqrt{3},4\sqrt{3},3\sqrt{3}\) मिलते हैं। (2+5-4-3=0) इसलिए मान (0) है।