( \left\(\frac{1}{5-\sqrt{21}}\right\)+\left\(\frac{1}{5+\sqrt{21}}\right\) ) का मान क्या है?

What is the value of ( \left\(\frac{1}{5-\sqrt{21}}\right\)+\left\(\frac{1}{5+\sqrt{21}}\right\) )?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \( \frac{5}{2} \)

Step 1

Concept

The common denominator is (25-21=4), and the numerator is (10). So the value is \( \frac{10}{4}=\frac{5}{2} \).

Step 2

Why this answer is correct

The correct answer is A. \( \frac{5}{2} \). The common denominator is (25-21=4), and the numerator is (10). So the value is \( \frac{10}{4}=\frac{5}{2} \).

Step 3

Exam Tip

समान हर (25-21=4) और अंश (10) है। इसलिए मान \( \frac{10}{4}=\frac{5}{2} \) है।

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Mathematics Answer, Explanation and Revision Hints

( \left\(\frac{1}{5-\sqrt{21}}\right\)+\left\(\frac{1}{5+\sqrt{21}}\right\) ) का मान क्या है? / What is the value of ( \left\(\frac{1}{5-\sqrt{21}}\right\)+\left\(\frac{1}{5+\sqrt{21}}\right\) )?

Correct Answer: A. \( \frac{5}{2} \). Explanation: समान हर (25-21=4) और अंश (10) है। इसलिए मान \( \frac{10}{4}=\frac{5}{2} \) है। / The common denominator is (25-21=4), and the numerator is (10). So the value is \( \frac{10}{4}=\frac{5}{2} \).

Which concept should I revise for this Mathematics MCQ?

The common denominator is (25-21=4), and the numerator is (10). So the value is \( \frac{10}{4}=\frac{5}{2} \).

What exam hint can help solve this Mathematics question?

समान हर (25-21=4) और अंश (10) है। इसलिए मान \( \frac{10}{4}=\frac{5}{2} \) है।