( \left\(\frac{1}{3-\sqrt{7}}\right\)+\left\(\frac{1}{3+\sqrt{7}}\right\) ) का मान क्या है?

What is the value of ( \left\(\frac{1}{3-\sqrt{7}}\right\)+\left\(\frac{1}{3+\sqrt{7}}\right\) )?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

The common denominator is (9-7=2), and the numerator is \(3+\sqrt{7}+3-\sqrt{7}=6\). So the value is \( \frac{6}{2}=3 \).

Step 2

Why this answer is correct

The correct answer is A. (3). The common denominator is (9-7=2), and the numerator is \(3+\sqrt{7}+3-\sqrt{7}=6\). So the value is \( \frac{6}{2}=3 \).

Step 3

Exam Tip

समान हर (9-7=2) और अंश \(3+\sqrt{7}+3-\sqrt{7}=6\) है। इसलिए मान \( \frac{6}{2}=3 \) है।

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Mathematics Answer, Explanation and Revision Hints

( \left\(\frac{1}{3-\sqrt{7}}\right\)+\left\(\frac{1}{3+\sqrt{7}}\right\) ) का मान क्या है? / What is the value of ( \left\(\frac{1}{3-\sqrt{7}}\right\)+\left\(\frac{1}{3+\sqrt{7}}\right\) )?

Correct Answer: A. (3). Explanation: समान हर (9-7=2) और अंश \(3+\sqrt{7}+3-\sqrt{7}=6\) है। इसलिए मान \( \frac{6}{2}=3 \) है। / The common denominator is (9-7=2), and the numerator is \(3+\sqrt{7}+3-\sqrt{7}=6\). So the value is \( \frac{6}{2}=3 \).

Which concept should I revise for this Mathematics MCQ?

The common denominator is (9-7=2), and the numerator is \(3+\sqrt{7}+3-\sqrt{7}=6\). So the value is \( \frac{6}{2}=3 \).

What exam hint can help solve this Mathematics question?

समान हर (9-7=2) और अंश \(3+\sqrt{7}+3-\sqrt{7}=6\) है। इसलिए मान \( \frac{6}{2}=3 \) है।