\( \frac{3+\sqrt{2}}{3-\sqrt{2}}+\frac{3-\sqrt{2}}{3+\sqrt{2}} \) का मान क्या है?

What is the value of \( \frac{3+\sqrt{2}}{3-\sqrt{2}}+\frac{3-\sqrt{2}}{3+\sqrt{2}} \)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \( \frac{22}{7} \)

Step 1

Concept

The value is ( \frac{\(3+\sqrt{2}\)2+\(3-\sqrt{2}\)2}{9-2} ). The numerator is (22) and the denominator is (7).

Step 2

Why this answer is correct

The correct answer is A. \( \frac{22}{7} \). The value is ( \frac{\(3+\sqrt{2}\)2+\(3-\sqrt{2}\)2}{9-2} ). The numerator is (22) and the denominator is (7).

Step 3

Exam Tip

मान ( \frac{\(3+\sqrt{2}\)2+\(3-\sqrt{2}\)2}{9-2} ) होगा। अंश (22) और हर (7) है।

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Mathematics Answer, Explanation and Revision Hints

\( \frac{3+\sqrt{2}}{3-\sqrt{2}}+\frac{3-\sqrt{2}}{3+\sqrt{2}} \) का मान क्या है? / What is the value of \( \frac{3+\sqrt{2}}{3-\sqrt{2}}+\frac{3-\sqrt{2}}{3+\sqrt{2}} \)?

Correct Answer: A. \( \frac{22}{7} \). Explanation: मान ( \frac{\(3+\sqrt{2}\)2+\(3-\sqrt{2}\)2}{9-2} ) होगा। अंश (22) और हर (7) है। / The value is ( \frac{\(3+\sqrt{2}\)2+\(3-\sqrt{2}\)2}{9-2} ). The numerator is (22) and the denominator is (7).

Which concept should I revise for this Mathematics MCQ?

The value is ( \frac{\(3+\sqrt{2}\)2+\(3-\sqrt{2}\)2}{9-2} ). The numerator is (22) and the denominator is (7).

What exam hint can help solve this Mathematics question?

मान ( \frac{\(3+\sqrt{2}\)2+\(3-\sqrt{2}\)2}{9-2} ) होगा। अंश (22) और हर (7) है।