\( \frac{1}{\sqrt{3}-\sqrt{2}}-\frac{1}{\sqrt{3}+\sqrt{2}} \) का मान क्या है?

What is the value of \( \frac{1}{\sqrt{3}-\sqrt{2}}-\frac{1}{\sqrt{3}+\sqrt{2}} \)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(2\sqrt{2}\)

Step 1

Concept

The common denominator is (3-2=1), and the numerator is ( \sqrt{3}+\sqrt{2}-\(\sqrt{3}-\sqrt{2}\)=2\sqrt{2} ).

Step 2

Why this answer is correct

The correct answer is A. \(2\sqrt{2}\). The common denominator is (3-2=1), and the numerator is ( \sqrt{3}+\sqrt{2}-\(\sqrt{3}-\sqrt{2}\)=2\sqrt{2} ).

Step 3

Exam Tip

समान हर (3-2=1) और अंश ( \sqrt{3}+\sqrt{2}-\(\sqrt{3}-\sqrt{2}\)=2\sqrt{2} ) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\( \frac{1}{\sqrt{3}-\sqrt{2}}-\frac{1}{\sqrt{3}+\sqrt{2}} \) का मान क्या है? / What is the value of \( \frac{1}{\sqrt{3}-\sqrt{2}}-\frac{1}{\sqrt{3}+\sqrt{2}} \)?

Correct Answer: A. \(2\sqrt{2}\). Explanation: समान हर (3-2=1) और अंश ( \sqrt{3}+\sqrt{2}-\(\sqrt{3}-\sqrt{2}\)=2\sqrt{2} ) है। / The common denominator is (3-2=1), and the numerator is ( \sqrt{3}+\sqrt{2}-\(\sqrt{3}-\sqrt{2}\)=2\sqrt{2} ).

Which concept should I revise for this Mathematics MCQ?

The common denominator is (3-2=1), and the numerator is ( \sqrt{3}+\sqrt{2}-\(\sqrt{3}-\sqrt{2}\)=2\sqrt{2} ).

What exam hint can help solve this Mathematics question?

समान हर (3-2=1) और अंश ( \sqrt{3}+\sqrt{2}-\(\sqrt{3}-\sqrt{2}\)=2\sqrt{2} ) है।