गुणोत्तर श्रेणी \(1,3,9,27,\ldots\) के पहले (7) पदों का योग क्या है?

What is the sum of the first (7) terms of the geometric progression \(1,3,9,27,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. (1093)

Step 1

Concept

\(S_7=\frac{3^7-1}{3-1}=1093\). In exams the form \(\frac{r^n-1}{r-1}\) is useful for (r>1).

Step 2

Why this answer is correct

The correct answer is A. (1093). \(S_7=\frac{3^7-1}{3-1}=1093\). In exams the form \(\frac{r^n-1}{r-1}\) is useful for (r>1).

Step 3

Exam Tip

\(S_7=\frac{3^7-1}{3-1}=1093\) है। परीक्षा में (r>1) के लिए \(\frac{r^n-1}{r-1}\) रूप उपयोगी है।

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Mathematics Answer, Explanation and Revision Hints

गुणोत्तर श्रेणी \(1,3,9,27,\ldots\) के पहले (7) पदों का योग क्या है? / What is the sum of the first (7) terms of the geometric progression \(1,3,9,27,\ldots\)?

Correct Answer: A. (1093). Explanation: \(S_7=\frac{3^7-1}{3-1}=1093\) है। परीक्षा में (r>1) के लिए \(\frac{r^n-1}{r-1}\) रूप उपयोगी है। / \(S_7=\frac{3^7-1}{3-1}=1093\). In exams the form \(\frac{r^n-1}{r-1}\) is useful for (r>1).

Which concept should I revise for this Mathematics MCQ?

\(S_7=\frac{3^7-1}{3-1}=1093\). In exams the form \(\frac{r^n-1}{r-1}\) is useful for (r>1).

What exam hint can help solve this Mathematics question?

\(S_7=\frac{3^7-1}{3-1}=1093\) है। परीक्षा में (r>1) के लिए \(\frac{r^n-1}{r-1}\) रूप उपयोगी है।