समांतर श्रेणी \(3,9,15,21,\ldots\) के पहले (10) पदों का योग क्या है?
What is the sum of the first (10) terms of the arithmetic progression \(3,9,15,21,\ldots\)?
Explanation opens after your attempt
Correct Answer
C. (300)
Concept
The first and tenth terms are (3) and (57), so the sum is (\frac{10(3+57)}{2}=300). Use the first and last terms for the sum.
Why this answer is correct
The correct answer is C. (300). The first and tenth terms are (3) and (57), so the sum is (\frac{10(3+57)}{2}=300). Use the first and last terms for the sum.
Exam Tip
पहला और दसवाँ पद (3) और (57) हैं, इसलिए योग (\frac{10(3+57)}{2}=300)। योग में पहला और अंतिम पद उपयोग करें।
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