\(\frac{\sqrt{98}+\sqrt{50}}{\sqrt{2}}\) का सरल मान क्या है?
What is the simplified value of \(\frac{\sqrt{98}+\sqrt{50}}{\sqrt{2}}\)?
Explanation opens after your attempt
A. (12)
Concept
\(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so division gives (12). Simplify the numerator first.
Why this answer is correct
The correct answer is A. (12). \(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so division gives (12). Simplify the numerator first.
Exam Tip
\(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\), इसलिए भाग देने पर (12) मिलता है। पहले अंश को सरल करें।
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