\(\sqrt{45}+\sqrt{125}-\sqrt{20}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{45}+\sqrt{125}-\sqrt{20}\)?
Explanation opens after your attempt
B. \(6\sqrt{5}\)
Concept
\(\sqrt{45}=3\sqrt{5}\), \(\sqrt{125}=5\sqrt{5}\) and \(\sqrt{20}=2\sqrt{5}\), so the answer is \(6\sqrt{5}\). Add and subtract coefficients of like radicals.
Why this answer is correct
The correct answer is B. \(6\sqrt{5}\). \(\sqrt{45}=3\sqrt{5}\), \(\sqrt{125}=5\sqrt{5}\) and \(\sqrt{20}=2\sqrt{5}\), so the answer is \(6\sqrt{5}\). Add and subtract coefficients of like radicals.
Exam Tip
\(\sqrt{45}=3\sqrt{5}\), \(\sqrt{125}=5\sqrt{5}\) और \(\sqrt{20}=2\sqrt{5}\), इसलिए उत्तर \(6\sqrt{5}\) है। समान मूलों के गुणांक जोड़ें और घटाएं।
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