\(\sqrt{3}+\sqrt{12}+\sqrt{27}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{3}+\sqrt{12}+\sqrt{27}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

D. \(6\sqrt{3}\)

Step 1

Concept

\(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\), so the total is \(6\sqrt{3}\). First convert all terms into like radicals.

Step 2

Why this answer is correct

The correct answer is D. \(6\sqrt{3}\). \(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\), so the total is \(6\sqrt{3}\). First convert all terms into like radicals.

Step 3

Exam Tip

\(\sqrt{12}=2\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\), इसलिए कुल \(6\sqrt{3}\) है। सभी पदों को पहले समान मूल में बदलें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(\sqrt{3}+\sqrt{12}+\sqrt{27}\) का सरल रूप क्या है? / What is the simplified form of \(\sqrt{3}+\sqrt{12}+\sqrt{27}\)?

Correct Answer: D. \(6\sqrt{3}\). Explanation: \(\sqrt{12}=2\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\), इसलिए कुल \(6\sqrt{3}\) है। सभी पदों को पहले समान मूल में बदलें। / \(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\), so the total is \(6\sqrt{3}\). First convert all terms into like radicals.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\), so the total is \(6\sqrt{3}\). First convert all terms into like radicals.

What exam hint can help solve this Mathematics question?

\(\sqrt{12}=2\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\), इसलिए कुल \(6\sqrt{3}\) है। सभी पदों को पहले समान मूल में बदलें।