\(\sqrt{28}+\sqrt{63}-\sqrt{7}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{28}+\sqrt{63}-\sqrt{7}\)?
Explanation opens after your attempt
Correct Answer
C. \(4\sqrt{7}\)
Concept
\(\sqrt{28}=2\sqrt{7}\) and \(\sqrt{63}=3\sqrt{7}\), so \(2\sqrt{7}+3\sqrt{7}-\sqrt{7}=4\sqrt{7}\). Add and subtract like radicals.
Why this answer is correct
The correct answer is C. \(4\sqrt{7}\). \(\sqrt{28}=2\sqrt{7}\) and \(\sqrt{63}=3\sqrt{7}\), so \(2\sqrt{7}+3\sqrt{7}-\sqrt{7}=4\sqrt{7}\). Add and subtract like radicals.
Exam Tip
\(\sqrt{28}=2\sqrt{7}\) और \(\sqrt{63}=3\sqrt{7}\), इसलिए \(2\sqrt{7}+3\sqrt{7}-\sqrt{7}=4\sqrt{7}\) है। समान मूलों को जोड़ें और घटाएं।
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