\(\sqrt{147}+\sqrt{75}-\sqrt{27}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{147}+\sqrt{75}-\sqrt{27}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(9\sqrt{3}\)

Step 1

Concept

\(\sqrt{147}=7\sqrt{3}\), \(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\), so the answer is \(9\sqrt{3}\). Add and subtract coefficients of like radicals.

Step 2

Why this answer is correct

The correct answer is A. \(9\sqrt{3}\). \(\sqrt{147}=7\sqrt{3}\), \(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\), so the answer is \(9\sqrt{3}\). Add and subtract coefficients of like radicals.

Step 3

Exam Tip

\(\sqrt{147}=7\sqrt{3}\), \(\sqrt{75}=5\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\), इसलिए उत्तर \(9\sqrt{3}\) है। समान मूलों के गुणांक जोड़ें और घटाएं।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(\sqrt{147}+\sqrt{75}-\sqrt{27}\) का सरल रूप क्या है? / What is the simplified form of \(\sqrt{147}+\sqrt{75}-\sqrt{27}\)?

Correct Answer: A. \(9\sqrt{3}\). Explanation: \(\sqrt{147}=7\sqrt{3}\), \(\sqrt{75}=5\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\), इसलिए उत्तर \(9\sqrt{3}\) है। समान मूलों के गुणांक जोड़ें और घटाएं। / \(\sqrt{147}=7\sqrt{3}\), \(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\), so the answer is \(9\sqrt{3}\). Add and subtract coefficients of like radicals.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{147}=7\sqrt{3}\), \(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\), so the answer is \(9\sqrt{3}\). Add and subtract coefficients of like radicals.

What exam hint can help solve this Mathematics question?

\(\sqrt{147}=7\sqrt{3}\), \(\sqrt{75}=5\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\), इसलिए उत्तर \(9\sqrt{3}\) है। समान मूलों के गुणांक जोड़ें और घटाएं।