\( \sqrt{128}+\sqrt{200}-\sqrt{72} \) का सरल रूप क्या है?
What is the simplified form of \( \sqrt{128}+\sqrt{200}-\sqrt{72} \)?
Explanation opens after your attempt
A. \(12\sqrt{2}\)
Concept
\( \sqrt{128}=8\sqrt{2} \), \( \sqrt{200}=10\sqrt{2} \), and \( \sqrt{72}=6\sqrt{2} \). So the result is \(12\sqrt{2}\).
Why this answer is correct
The correct answer is A. \(12\sqrt{2}\). \( \sqrt{128}=8\sqrt{2} \), \( \sqrt{200}=10\sqrt{2} \), and \( \sqrt{72}=6\sqrt{2} \). So the result is \(12\sqrt{2}\).
Exam Tip
\( \sqrt{128}=8\sqrt{2} \), \( \sqrt{200}=10\sqrt{2} \), और \( \sqrt{72}=6\sqrt{2} \)। इसलिए परिणाम \(12\sqrt{2}\) है।
Login to save your score, XP, coins and progress.
