\( \frac{1}{\sqrt{13}+\sqrt{12}} \) का परिमेय हर वाला रूप क्या है?

What is the rationalised form of \( \frac{1}{\sqrt{13}+\sqrt{12}} \)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \( \sqrt{13}-2\sqrt{3} \)

Step 1

Concept

The denominator is \( \sqrt{13}+2\sqrt{3} \) and its conjugate is \( \sqrt{13}-2\sqrt{3} \). The denominator becomes (13-12=1).

Step 2

Why this answer is correct

The correct answer is A. \( \sqrt{13}-2\sqrt{3} \). The denominator is \( \sqrt{13}+2\sqrt{3} \) and its conjugate is \( \sqrt{13}-2\sqrt{3} \). The denominator becomes (13-12=1).

Step 3

Exam Tip

हर \( \sqrt{13}+2\sqrt{3} \) है और संयुग्मी \( \sqrt{13}-2\sqrt{3} \) होगा। हर (13-12=1) बनता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\( \frac{1}{\sqrt{13}+\sqrt{12}} \) का परिमेय हर वाला रूप क्या है? / What is the rationalised form of \( \frac{1}{\sqrt{13}+\sqrt{12}} \)?

Correct Answer: A. \( \sqrt{13}-2\sqrt{3} \). Explanation: हर \( \sqrt{13}+2\sqrt{3} \) है और संयुग्मी \( \sqrt{13}-2\sqrt{3} \) होगा। हर (13-12=1) बनता है। / The denominator is \( \sqrt{13}+2\sqrt{3} \) and its conjugate is \( \sqrt{13}-2\sqrt{3} \). The denominator becomes (13-12=1).

Which concept should I revise for this Mathematics MCQ?

The denominator is \( \sqrt{13}+2\sqrt{3} \) and its conjugate is \( \sqrt{13}-2\sqrt{3} \). The denominator becomes (13-12=1).

What exam hint can help solve this Mathematics question?

हर \( \sqrt{13}+2\sqrt{3} \) है और संयुग्मी \( \sqrt{13}-2\sqrt{3} \) होगा। हर (13-12=1) बनता है।