\( \frac{1}{6+\sqrt{35}} \) का परिमेय हर वाला रूप क्या है?

What is the rationalised form of \( \frac{1}{6+\sqrt{35}} \)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(6-\sqrt{35}\)

Step 1

Concept

Multiplying by the conjugate \(6-\sqrt{35}\) makes the denominator (36-35=1). So the rationalised form is \(6-\sqrt{35}\).

Step 2

Why this answer is correct

The correct answer is A. \(6-\sqrt{35}\). Multiplying by the conjugate \(6-\sqrt{35}\) makes the denominator (36-35=1). So the rationalised form is \(6-\sqrt{35}\).

Step 3

Exam Tip

संयुग्मी \(6-\sqrt{35}\) से गुणा करने पर हर (36-35=1) बनता है। इसलिए परिमेय हर वाला रूप \(6-\sqrt{35}\) है।

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Mathematics Answer, Explanation and Revision Hints

\( \frac{1}{6+\sqrt{35}} \) का परिमेय हर वाला रूप क्या है? / What is the rationalised form of \( \frac{1}{6+\sqrt{35}} \)?

Correct Answer: A. \(6-\sqrt{35}\). Explanation: संयुग्मी \(6-\sqrt{35}\) से गुणा करने पर हर (36-35=1) बनता है। इसलिए परिमेय हर वाला रूप \(6-\sqrt{35}\) है। / Multiplying by the conjugate \(6-\sqrt{35}\) makes the denominator (36-35=1). So the rationalised form is \(6-\sqrt{35}\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate \(6-\sqrt{35}\) makes the denominator (36-35=1). So the rationalised form is \(6-\sqrt{35}\).

What exam hint can help solve this Mathematics question?

संयुग्मी \(6-\sqrt{35}\) से गुणा करने पर हर (36-35=1) बनता है। इसलिए परिमेय हर वाला रूप \(6-\sqrt{35}\) है।