\(\frac{1}{3-\sqrt{2}}\) का परिमेयकृत रूप क्या है?

What is the rationalised form of \(\frac{1}{3-\sqrt{2}}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\frac{3+\sqrt{2}}{7}\)

Step 1

Concept

Multiplying by the conjugate makes the denominator (9-2=7). So the form is \(\frac{3+\sqrt{2}}{7}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{3+\sqrt{2}}{7}\). Multiplying by the conjugate makes the denominator (9-2=7). So the form is \(\frac{3+\sqrt{2}}{7}\).

Step 3

Exam Tip

संयुग्मी से गुणा करने पर हर (9-2=7) बनता है। इसलिए रूप \(\frac{3+\sqrt{2}}{7}\) है।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{1}{3-\sqrt{2}}\) का परिमेयकृत रूप क्या है? / What is the rationalised form of \(\frac{1}{3-\sqrt{2}}\)?

Correct Answer: A. \(\frac{3+\sqrt{2}}{7}\). Explanation: संयुग्मी से गुणा करने पर हर (9-2=7) बनता है। इसलिए रूप \(\frac{3+\sqrt{2}}{7}\) है। / Multiplying by the conjugate makes the denominator (9-2=7). So the form is \(\frac{3+\sqrt{2}}{7}\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate makes the denominator (9-2=7). So the form is \(\frac{3+\sqrt{2}}{7}\).

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर हर (9-2=7) बनता है। इसलिए रूप \(\frac{3+\sqrt{2}}{7}\) है।