गुणोत्तर श्रेणी \(256,128,64,32,\ldots\) का नौवाँ पद क्या है?
What is the ninth term of the geometric progression \(256,128,64,32,\ldots\)?
Explanation opens after your attempt
A. (1)
Concept
Here \(r=\frac{1}{2}\) so (a_9=256\cdot\left\(\frac{1}{2}\right\)8=1). In exams use the fractional ratio in decreasing progressions.
Why this answer is correct
The correct answer is A. (1). Here \(r=\frac{1}{2}\) so (a_9=256\cdot\left\(\frac{1}{2}\right\)8=1). In exams use the fractional ratio in decreasing progressions.
Exam Tip
यहाँ \(r=\frac{1}{2}\) है इसलिए (a_9=256\cdot\left\(\frac{1}{2}\right\)8=1) है। परीक्षा में घटती श्रेणी में भिन्न अनुपात लगाएँ।
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