गुणोत्तर श्रेणी \(256,128,64,32,\ldots\) का नौवाँ पद क्या है?

What is the ninth term of the geometric progression \(256,128,64,32,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. (1)

Step 1

Concept

Here \(r=\frac{1}{2}\) so (a_9=256\cdot\left\(\frac{1}{2}\right\)8=1). In exams use the fractional ratio in decreasing progressions.

Step 2

Why this answer is correct

The correct answer is A. (1). Here \(r=\frac{1}{2}\) so (a_9=256\cdot\left\(\frac{1}{2}\right\)8=1). In exams use the fractional ratio in decreasing progressions.

Step 3

Exam Tip

यहाँ \(r=\frac{1}{2}\) है इसलिए (a_9=256\cdot\left\(\frac{1}{2}\right\)8=1) है। परीक्षा में घटती श्रेणी में भिन्न अनुपात लगाएँ।

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Mathematics Answer, Explanation and Revision Hints

गुणोत्तर श्रेणी \(256,128,64,32,\ldots\) का नौवाँ पद क्या है? / What is the ninth term of the geometric progression \(256,128,64,32,\ldots\)?

Correct Answer: A. (1). Explanation: यहाँ \(r=\frac{1}{2}\) है इसलिए (a_9=256\cdot\left\(\frac{1}{2}\right\)8=1) है। परीक्षा में घटती श्रेणी में भिन्न अनुपात लगाएँ। / Here \(r=\frac{1}{2}\) so (a_9=256\cdot\left\(\frac{1}{2}\right\)8=1). In exams use the fractional ratio in decreasing progressions.

Which concept should I revise for this Mathematics MCQ?

Here \(r=\frac{1}{2}\) so (a_9=256\cdot\left\(\frac{1}{2}\right\)8=1). In exams use the fractional ratio in decreasing progressions.

What exam hint can help solve this Mathematics question?

यहाँ \(r=\frac{1}{2}\) है इसलिए (a_9=256\cdot\left\(\frac{1}{2}\right\)8=1) है। परीक्षा में घटती श्रेणी में भिन्न अनुपात लगाएँ।