गुणोत्तर श्रेणी \(1024,512,256,128,\ldots\) का नौवाँ पद क्या है?

What is the ninth term of the geometric progression \(1024,512,256,128,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (4)

Step 1

Concept

Here \(r=\frac{1}{2}\), so (a_9=1024\cdot\left\(\frac{1}{2}\right\)8=4). In exams, apply fractional ratios carefully in decreasing GPs.

Step 2

Why this answer is correct

The correct answer is B. (4). Here \(r=\frac{1}{2}\), so (a_9=1024\cdot\left\(\frac{1}{2}\right\)8=4). In exams, apply fractional ratios carefully in decreasing GPs.

Step 3

Exam Tip

यहाँ \(r=\frac{1}{2}\) है, इसलिए (a_9=1024\cdot\left\(\frac{1}{2}\right\)8=4) है। परीक्षा में घटती GP में भिन्न अनुपात सावधानी से लगाएँ।

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Mathematics Answer, Explanation and Revision Hints

गुणोत्तर श्रेणी \(1024,512,256,128,\ldots\) का नौवाँ पद क्या है? / What is the ninth term of the geometric progression \(1024,512,256,128,\ldots\)?

Correct Answer: B. (4). Explanation: यहाँ \(r=\frac{1}{2}\) है, इसलिए (a_9=1024\cdot\left\(\frac{1}{2}\right\)8=4) है। परीक्षा में घटती GP में भिन्न अनुपात सावधानी से लगाएँ। / Here \(r=\frac{1}{2}\), so (a_9=1024\cdot\left\(\frac{1}{2}\right\)8=4). In exams, apply fractional ratios carefully in decreasing GPs.

Which concept should I revise for this Mathematics MCQ?

Here \(r=\frac{1}{2}\), so (a_9=1024\cdot\left\(\frac{1}{2}\right\)8=4). In exams, apply fractional ratios carefully in decreasing GPs.

What exam hint can help solve this Mathematics question?

यहाँ \(r=\frac{1}{2}\) है, इसलिए (a_9=1024\cdot\left\(\frac{1}{2}\right\)8=4) है। परीक्षा में घटती GP में भिन्न अनुपात सावधानी से लगाएँ।