अनुक्रम \(2,5,10,17,\ldots\) का (n)वाँ पद कौन-सा है?

What is the (n)th term of the sequence \(2,5,10,17,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. \(n^2+1\)

Step 1

Concept

The terms are \(1^2+1,2^2+1,3^2+1,\ldots\), so \(a_n=n^2+1\). Recognize the square pattern.

Step 2

Why this answer is correct

The correct answer is A. \(n^2+1\). The terms are \(1^2+1,2^2+1,3^2+1,\ldots\), so \(a_n=n^2+1\). Recognize the square pattern.

Step 3

Exam Tip

पद \(1^2+1,2^2+1,3^2+1,\ldots\) के रूप में हैं, इसलिए \(a_n=n^2+1\)। वर्ग वाले पैटर्न को पहचानें।

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Mathematics Answer, Explanation and Revision Hints

अनुक्रम \(2,5,10,17,\ldots\) का (n)वाँ पद कौन-सा है? / What is the (n)th term of the sequence \(2,5,10,17,\ldots\)?

Correct Answer: A. \(n^2+1\). Explanation: पद \(1^2+1,2^2+1,3^2+1,\ldots\) के रूप में हैं, इसलिए \(a_n=n^2+1\)। वर्ग वाले पैटर्न को पहचानें। / The terms are \(1^2+1,2^2+1,3^2+1,\ldots\), so \(a_n=n^2+1\). Recognize the square pattern.

Which concept should I revise for this Mathematics MCQ?

The terms are \(1^2+1,2^2+1,3^2+1,\ldots\), so \(a_n=n^2+1\). Recognize the square pattern.

What exam hint can help solve this Mathematics question?

पद \(1^2+1,2^2+1,3^2+1,\ldots\) के रूप में हैं, इसलिए \(a_n=n^2+1\)। वर्ग वाले पैटर्न को पहचानें।