गुणोत्तर श्रेढ़ी \(4,12,36,\ldots\) का (n)वाँ पद कौन-सा है?

What is the (n)th term of the geometric progression \(4,12,36,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. \(4\cdot3^{n-1}\)

Step 1

Concept

The first term is (4) and the ratio is (3), so \(a_n=4\cdot3^{n-1}\). In the geometric rule, the exponent is (n-1).

Step 2

Why this answer is correct

The correct answer is A. \(4\cdot3^{n-1}\). The first term is (4) and the ratio is (3), so \(a_n=4\cdot3^{n-1}\). In the geometric rule, the exponent is (n-1).

Step 3

Exam Tip

पहला पद (4) और अनुपात (3) है, इसलिए \(a_n=4\cdot3^{n-1}\)। गुणोत्तर नियम में घात (n-1) होती है।

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Mathematics Answer, Explanation and Revision Hints

गुणोत्तर श्रेढ़ी \(4,12,36,\ldots\) का (n)वाँ पद कौन-सा है? / What is the (n)th term of the geometric progression \(4,12,36,\ldots\)?

Correct Answer: A. \(4\cdot3^{n-1}\). Explanation: पहला पद (4) और अनुपात (3) है, इसलिए \(a_n=4\cdot3^{n-1}\)। गुणोत्तर नियम में घात (n-1) होती है। / The first term is (4) and the ratio is (3), so \(a_n=4\cdot3^{n-1}\). In the geometric rule, the exponent is (n-1).

Which concept should I revise for this Mathematics MCQ?

The first term is (4) and the ratio is (3), so \(a_n=4\cdot3^{n-1}\). In the geometric rule, the exponent is (n-1).

What exam hint can help solve this Mathematics question?

पहला पद (4) और अनुपात (3) है, इसलिए \(a_n=4\cdot3^{n-1}\)। गुणोत्तर नियम में घात (n-1) होती है।