अनुक्रम \(10,18,28,40,\ldots\) का सामान्य पद क्या है?

What is the general term of the sequence \(10,18,28,40,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

D. \(a_n=n^2+5n+4\)

Step 1

Concept

\(n^2+5n+4\) gives (10,18,28,40). In exams test the rule on the first four terms.

Step 2

Why this answer is correct

The correct answer is D. \(a_n=n^2+5n+4\). \(n^2+5n+4\) gives (10,18,28,40). In exams test the rule on the first four terms.

Step 3

Exam Tip

\(n^2+5n+4\) से (10,18,28,40) मिलते हैं। परीक्षा में पहले चार पदों पर नियम जाँचें।

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Mathematics Answer, Explanation and Revision Hints

अनुक्रम \(10,18,28,40,\ldots\) का सामान्य पद क्या है? / What is the general term of the sequence \(10,18,28,40,\ldots\)?

Correct Answer: D. \(a_n=n^2+5n+4\). Explanation: \(n^2+5n+4\) से (10,18,28,40) मिलते हैं। परीक्षा में पहले चार पदों पर नियम जाँचें। / \(n^2+5n+4\) gives (10,18,28,40). In exams test the rule on the first four terms.

Which concept should I revise for this Mathematics MCQ?

\(n^2+5n+4\) gives (10,18,28,40). In exams test the rule on the first four terms.

What exam hint can help solve this Mathematics question?

\(n^2+5n+4\) से (10,18,28,40) मिलते हैं। परीक्षा में पहले चार पदों पर नियम जाँचें।