अनुक्रम \(0,5,12,21,\ldots\) का सामान्य पद क्या है?
What is the general term of the sequence \(0,5,12,21,\ldots\)?
Explanation opens after your attempt
B. \(a_n=n^2+n-2\)
Concept
\(n^2+n-2\) gives (0,5,12,21). In exams test a quadratic rule on the first four terms.
Why this answer is correct
The correct answer is B. \(a_n=n^2+n-2\). \(n^2+n-2\) gives (0,5,12,21). In exams test a quadratic rule on the first four terms.
Exam Tip
\(n^2+n-2\) से (0,5,12,21) मिलते हैं। परीक्षा में वर्गीय नियम को पहले चार पदों पर जाँचें।
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