गुणोत्तर श्रेणी \(81,27,9,3,\ldots\) का सामान्य पद क्या है?
What is the general term of the geometric progression \(81,27,9,3,\ldots\)?
Explanation opens after your attempt
Correct Answer
B. (a_n=81\cdot\left\(\frac{1}{3}\right\)^{n-1})
Concept
The first term is (81) and the ratio is \(\frac{1}{3}\), so the correct rule is (81\cdot\left\(\frac{1}{3}\right\)^{n-1}). In exams write the fractional ratio in a decreasing GP.
Why this answer is correct
The correct answer is B. (a_n=81\cdot\left\(\frac{1}{3}\right\)^{n-1}). The first term is (81) and the ratio is \(\frac{1}{3}\), so the correct rule is (81\cdot\left\(\frac{1}{3}\right\)^{n-1}). In exams write the fractional ratio in a decreasing GP.
Exam Tip
पहला पद (81) और अनुपात \(\frac{1}{3}\) है इसलिए सही नियम (81\cdot\left\(\frac{1}{3}\right\)^{n-1}) है। परीक्षा में घटती GP में भिन्न अनुपात लिखें।
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