अनुक्रम \(2,4,7,11,16,\ldots\) में (20)वाँ पद क्या होगा?

What is the (20)th term of the sequence \(2,4,7,11,16,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (211)

Step 1

Concept

It adds consecutive numbers starting from (1), so (a_n=1+\frac{n(n+1)}{2}). Thus \(a_{20}=1+\frac{20\times21}{2}=211\).

Step 2

Why this answer is correct

The correct answer is C. (211). It adds consecutive numbers starting from (1), so (a_n=1+\frac{n(n+1)}{2}). Thus \(a_{20}=1+\frac{20\times21}{2}=211\).

Step 3

Exam Tip

यह (1) से शुरू होकर क्रमागत संख्याएँ जोड़ता है और (a_n=1+\frac{n(n+1)}{2}) है। \(a_{20}=1+\frac{20\times21}{2}=211\) है।

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Mathematics Answer, Explanation and Revision Hints

अनुक्रम \(2,4,7,11,16,\ldots\) में (20)वाँ पद क्या होगा? / What is the (20)th term of the sequence \(2,4,7,11,16,\ldots\)?

Correct Answer: C. (211). Explanation: यह (1) से शुरू होकर क्रमागत संख्याएँ जोड़ता है और (a_n=1+\frac{n(n+1)}{2}) है। \(a_{20}=1+\frac{20\times21}{2}=211\) है। / It adds consecutive numbers starting from (1), so (a_n=1+\frac{n(n+1)}{2}). Thus \(a_{20}=1+\frac{20\times21}{2}=211\).

Which concept should I revise for this Mathematics MCQ?

It adds consecutive numbers starting from (1), so (a_n=1+\frac{n(n+1)}{2}). Thus \(a_{20}=1+\frac{20\times21}{2}=211\).

What exam hint can help solve this Mathematics question?

यह (1) से शुरू होकर क्रमागत संख्याएँ जोड़ता है और (a_n=1+\frac{n(n+1)}{2}) है। \(a_{20}=1+\frac{20\times21}{2}=211\) है।