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What caution is necessary while proving the irrationality of √2 and √3?

Answer and explanation

Correct answer: The fraction should first be assumed in lowest coprime form

The governing idea is proof by contradiction. To test whether √2 or √3 can be rational, we assume it equals a fraction a/b, where a and b are integers, b is non-zero, and gcd(a,b)=1. The lowest-form condition is essential: after squaring and using divisibility, the proof generally shows that both a and b must be even. That is impossible for a coprime pair because a common factor 2 would remain. Therefore the original rational assumption fails. Option A is correct. A zero denominator is forbidden, a decimal approximation cannot establish irrationality, and equal numerator and denominator is not part of the argument.

Related tags

Number-SystemsIrrationality-ProofLowest-FormProof Of Irrationality Of Square Root 2 And Square Root 3Number SystemsMathematicsClass 9 Mcq

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